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-6n^2+2n=-8
We move all terms to the left:
-6n^2+2n-(-8)=0
We add all the numbers together, and all the variables
-6n^2+2n+8=0
a = -6; b = 2; c = +8;
Δ = b2-4ac
Δ = 22-4·(-6)·8
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-14}{2*-6}=\frac{-16}{-12} =1+1/3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+14}{2*-6}=\frac{12}{-12} =-1 $
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